8x-40/x^2-5x

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Solution for 8x-40/x^2-5x equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

8*x-(5*x)-(40/(x^2)) = 0

8*x-5*x-40*x^-2 = 0

3*x-40*x^-2 = 0

x*(3-40*x^-3) = 0

-40*x^-3 = -3 // : -40

x^-3 = 3/40

-3 < 0

1/(x^3) = 3/40 // * x^3

1 = 3/40*x^3 // : 3/40

40/3 = x^3

x^3 = 40/3 // ^ 1/3

x = (40/3)^(1/3)

x = 0

x = 0

x in { 0} 

x = (40/3)^(1/3)

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